3y^2-2y-10=2y^2+y

Solution for 3y^2-2y-10=2y^2+y equation:

3y^2-2y-10=2y^2+y

We move all terms to the left:

3y^2-2y-10-(2y^2+y)=0

We get rid of parentheses

3y^2-2y^2-2y-y-10=0

We add all the numbers together, and all the variables

y^2-3y-10=0

a = 1; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·1·(-10)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*1}=\frac{-4}{2}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*1}=\frac{10}{2}
=5
$